LIVE Global accident monitoring — updating every 15 minutes
Free Tool · Crash Physics

Car Crash Force Calculator

Quick answer: a car that hits a solid object at 30 mph and crushes 0.6 m averages about 15 g; a belted occupant averages about 10 g, an unbelted one far more. The impact equals falling 9.2 m (30 ft), about three storeys. Formula: average deceleration = v² ÷ (2 × stopping distance); force = mass × deceleration.

Updated · formulas checked against the sources below

15.3 g
Car: average deceleration
225 kN average force on a 1,500 kg car
10.2 g
Belted occupant: average
7.5 kN on a 75 kg person; peaks near 16 g
9.2 m
Same as falling from
30 ft, about 3.1 storeys
89 ms
Crash duration (car)
135 kJ of movement energy

Default shown: 30 mph into a solid object, 1,500 kg car, 75 kg occupant with belt and airbag, 0.6 m of crumple. Change any value above.

Not a substitute for an accident reconstruction expert. These are textbook physics estimates for learning and rough checks. A real reconstruction measures the road, the vehicles, the marks and the event data recorder, and can give a different answer. Do not rely on this page for an insurance claim, a court case or a police report.

The formula

How crash force and G-force are worked out

When a car stops, its speed has to go to zero over some distance. The shorter that distance, the harder the stop. Assuming an even (constant) deceleration:

a = v² ÷ (2 × d)    G = a ÷ 9.81    F = m × a    t = 2 × d ÷ v

where v is the speed in m/s (mph × 0.447, or km/h ÷ 3.6), d the stopping distance in metres, m the mass in kg and t the time the stop takes. The "equivalent fall height" uses the same physics backwards: a fall from h = v² ÷ (2 × 9.81) metres ends at speed v.

Worked example

A 1,500 kg car hits a concrete wall at 30 mph = 13.4 m/s, and its front crushes 0.6 m.

a = 13.4² ÷ (2 × 0.6) = 180 ÷ 1.2 ≈ 150 m/s² ≈ 15.3 g
F = 1,500 × 150 ≈ 225,000 N ≈ 225 kN    t = 2 × 0.6 ÷ 13.4 ≈ 0.09 s

The belted driver (75 kg) moves about 0.3 m further as the belt stretches and the airbag compresses, so stops over 0.9 m: about 10.2 g on average, a load of about 7.5 kN spread across the pelvis and chest. Without a belt the driver keeps going at 30 mph and stops against the wheel or dashboard in perhaps 5 cm: about 183 g on average. The physics is the same; only the stopping distance changes.

Average versus peak

Real crash pulses are not flat. If the deceleration rises and falls like a half sine wave, the peak is about π/2 ≈ 1.6 times the average, which is why the calculator also shows an estimated peak. Crash-test sensors record the full curve; this page cannot.

Table

Crash speed, G-force and equivalent fall height

Solid-object crash; car crumple 0.6 m; belted occupant 0.9 m; car 1,500 kg. A storey is taken as 3 m.

SpeedFall heightStoreysCar averageBelted occupantEnergy (1,500 kg)
10 mph (16 km/h)1.0 m / 3 ft0.32 g1 g15 kJ
20 mph (32 km/h)4.1 m / 13 ft1.47 g5 g60 kJ
30 mph (48 km/h)9.2 m / 30 ft3.115 g10 g135 kJ
40 mph (64 km/h)16.3 m / 53 ft5.427 g18 g240 kJ
50 mph (80 km/h)25.5 m / 84 ft8.542 g28 g375 kJ
60 mph (97 km/h)36.7 m / 120 ft12.261 g41 g540 kJ
70 mph (113 km/h)49.9 m / 164 ft16.683 g55 g734 kJ
80 mph (129 km/h)65.2 m / 214 ft21.7109 g72 g959 kJ
Table

The same in km/h

SpeedFall heightStoreysCar averageBelted occupantEnergy (1,500 kg)
30 km/h (19 mph)3.5 m1.26 g4 g52 kJ
50 km/h (31 mph)9.8 m3.316 g11 g145 kJ
70 km/h (43 mph)19.3 m6.432 g21 g284 kJ
90 km/h (56 mph)31.9 m10.653 g35 g469 kJ
110 km/h (68 mph)47.6 m15.979 g53 g700 kJ
130 km/h (81 mph)66.5 m22.2111 g74 g978 kJ

Doubling the speed quadruples the energy, the fall height and (for the same crumple distance) the G-force. Real crumple zones are tuned for test speeds, so at very high speeds the structure runs out of crush distance and the forces rise faster still.

Limits

Assumptions

  • Solid object. The car stops completely, as in a crash into a wall or a large tree. Crashes into another car, a hedge or a guard rail usually involve a smaller change of speed and longer stops.
  • Even deceleration. Real crashes have peaks; the page shows a half-sine peak estimate (about 1.6 × average).
  • Distances are illustrations. 0.5–1 m of crumple is typical of a car front in a severe frontal crash; the extra 0.2–0.3 m for a belted occupant and the 5 cm for an unbelted one are round numbers chosen to show the effect, not measurements of any car.
  • G-force is not injury. Whether a person is hurt depends on the direction of the force, how long it lasts, where on the body it lands and the person's age and health.
  • Head-on crashes. Two equal cars meeting head-on at 50 mph each stop from 50 mph, much like hitting a solid wall at 50 mph, not 100 mph. A lighter car meeting a heavier one has a larger change of speed.

For context, official crash tests use speeds chosen to be survivable for a belted adult in a well-designed car: NHTSA's frontal test is run at 35 mph into a rigid barrier, and the IIHS frontal overlap tests at 40 mph. See the crash test ratings for any model.

Questions

Crash forces — FAQ

How many g's is a car crash?
It depends on the speed and on how far the car and the person travel while stopping. In a 30 mph (48 km/h) crash into something solid, a car whose front crushes 0.6 m averages about 15 g; a belted occupant who moves another 0.3 m with the belt and airbag averages about 10 g, with short peaks higher than the average. An unbelted person who stops against the dashboard in a few centimetres can see well over 100 g for a split second.
How do you calculate the impact force of a car crash?
Average force = mass × average deceleration, and average deceleration = v² ÷ (2 × stopping distance). So F = m × v² ÷ (2d). A 1,500 kg car stopping from 30 mph (13.4 m/s) in 0.6 m takes an average force of about 225 kN, roughly 15 times its own weight.
A car crash at 30 mph is like falling from how high?
About 9.2 m (30 ft), roughly the roof of a three-storey building, because a fall from that height ends at the same speed (h = v² ÷ 2g). At 60 mph the equivalent fall is four times higher: about 37 m (120 ft), around 12 storeys.
Why does a seatbelt reduce the force so much?
The force on your body depends on how far you travel while you stop. A belt (with its small stretch and the airbag) ties you to the car, so you use the crumple zone plus a little extra to slow down, and the load is spread over the strong pelvis and ribcage. Without a belt you keep moving at the original speed until you hit the wheel, dashboard or windscreen and stop in a few centimetres, so the average force is many times higher.
Does a heavier car crash with more force?
Against a solid wall, the G-force does not depend on mass: a heavy and a light car stopping from the same speed over the same distance see the same deceleration, though the heavier car needs more force. In a crash between two vehicles, momentum is shared, so the lighter vehicle has the larger change of speed and its occupants take the bigger G-load.
Sources

Sources and method

Method: a = v²/(2d), G = a/9.80665, F = m·a, t = 2d/v, h = v²/(2·9.80665), energy = ½·m·v²; peak ≈ π/2 × average for a half-sine pulse. Weights in lb are converted at 0.4536 kg. The calculator runs in your browser. Checked 2026-11-02.